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arXiv · 1612.08158

$(1^3+1)(2^3+1)\cdots(n^3+1)$ is not a cube

Chuan Ze Niu
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Abstract

For a positive integer $n,$ define $$C_n=\prod_{k=1}^n(k^3+1).$$ In this paper we prove that there are no cubes in the integer sequence $C_n,~n=1,2,\cdots.$

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Chuan Ze Niu. 2016-12-24. $(1^3+1)(2^3+1)\cdots(n^3+1)$ is not a cube. https://arxiv.org/abs/1612.08158

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