A note on a noetherian fully bounded ring

Abstract

We prove the following;Theorem:Let R be a prime noetherian ring with k.dimR = n, n a finite non-negative integer. We refer the reader to the definitions (1.1) of this paper.For a fixed non-negative integer m, m<n let Xm be the full set of m-prime ideals p of R and let cm = the set of elements c in R with k-dim(R/cR)< m and let vm = Intersection c(p), for all p in xm.Let c= family of Right ideals I of R such that I intersects cm nontrivially and let v=family of right ideals I of R such that I intersects vm nontrivially.Call g an m-gabriel filter if g=family of Right ideals J of R with k-dim.(R/J)< m.For any simple right module W over any extension ring S of R we denote by r(w) the right annihilator in S of W. Suppose any m critical right R module M with Ass. M = p is such that k.dim. M = R/p = m. Then the following conditions are equivalent:(a) xm has the right intersection condition. (b)(i) g=v.Then vm is a right ore set in R.Let Rv denote the quotient ring of R at the right ore set vm. (ii)Moreover then any simple Rv module say Wv with r(Wv)= qv is a torsion free Rv/qv module. (c)(i)g=c.Then cm is a right ore set in R. Let Rc denote the quotient ring of R at the right ore set cm. (ii) Moreover then any simple Rc module say Wc with r(Wc)=qc is a torsion free Rc/qc module. We may mention that this theorem is proved under a weaker hypothesis on a prime noetherian ring than for a prime noetherian ring that is either fully bounded or has the bijective Gabriel correspondence.In particular the theorem remains true always for these rings for all nonnegative integers m, m<n.Moreover the theorem is true if we replace k-dim. R =n, n finite by any ordinal number.