arXiv · 2502.09109
On a Question of Hamkins'
Abstract
Joel Hamkins asks whether there is a $Π^0_1$-formula $ρ(x)$ such that $ρ({\ulcorner ϕ\urcorner})$ is independent over ${\sf PA}+ϕ$, if this theory is consistent, where this construction is extensional in $ϕ$ with respect to {\sf PA}-provable equivalence. We show that there can be no such extensional Rosser formula of any complexity. We give a positive answer to Hamkins' question for the case where we replace Extensionality by a weaker demand that we call \emph{Conditional Extensionality}. For this case, we prove an even stronger result, to wit, there is a $Π^0_1$-formula $ρ(x)$ that is extensional and $Π^0_1$-flexible. We leave one important question open: what happens when we weaken Extensionality to Consistent Extensionality, i.e., Extensionality for consistent extensions?
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Albert Visser. 2026-03-06. On a Question of Hamkins'. https://arxiv.org/abs/2502.09109
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