Conditional Cube Attack on Round-Reduced ASCON

Abstract

This paper evaluates the secure level of authenticated encryption \textsc{Ascon} against cube-like method. \textsc{Ascon} submitted by Dobraunig \emph{et~al.} is one of 16 survivors of the 3rd round CAESAR competition. The cube-like method is first used by Dinur \emph{et~al.} to analyze Keccak keyed modes. At CT-RSA 2015, Dobraunig \emph{et~al.} applied this method to 5/6-round reduced \textsc{Ascon}, whose structure is similar to Keccak keyed modes. However, for \textsc{Ascon} the non-linear layer is more complex and state is much smaller, which make it hard for the attackers to select enough cube variables that do not multiply with each other after the first round. This seems to be the reason why the best previous key-recovery attack is on 6-round \textsc{Ascon}, while for Keccak keyed modes (Keccak-MAC and Keyak) the attacked round is no less than 7-round. In this paper, we generalize the conditional cube attack proposed by Huang \emph{et~al.}, and find new cubes depending on some key bit conditions for 5/6-round reduced \textsc{Ascon}, and translate the previous theoretic 6-round attack with $2^{66}$ time complexity to a practical one with $2^{40}$ time complexity. Moreover, we propose the first 7-round key-recovery attack on \textsc{Ascon}. By introducing \emph{the cube-like key-subset technique}, we divide the full key space into many subsets according to different key conditions. For each key subset, we launch the cube tester to determine if the key falls into it. Finally, we recover the full key space by testing all the key subsets. The total time complexity is about $2^{103.9}$. In addition, for a weak-key subset, whose size is $2^{117}$, the attack is more efficient and costs only $2^{77}$ time complexity. Those attacks do not threaten the full round (12 rounds) \textsc{Ascon}.