Does NP not equal P?

C. Sauerbier

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arXiv · cs/0209015

Does NP not equal P?

C. Sauerbier

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Abstract

Stephen Cook posited SAT is NP-Complete in 1971. If SAT is NP-Complete then, as is generally accepted, any polynomial solution of it must also present a polynomial solution of all NP decision problems. It is here argued, however, that NP is not of necessity equivalent to P where it is shown that SAT is contained in P. This due to a paradox, of nature addressed by both Godel and Russell, in regards to the P-NP system in total.

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C. Sauerbier. 2002-09-11. Does NP not equal P?. https://arxiv.org/abs/cs/0209015

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