arXiv · math/0607491
A note on primes dividing alternating sums
Abstract
We define A_n=\sum_{i=1}^n (-1)^i\frac{1}{i} and we show that, for every prime p, there exists a number n such that A_n\equiv 0 (mod p).
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Antonio M. Oller Marcen. 2006-07-20. A note on primes dividing alternating sums. https://arxiv.org/abs/math/0607491
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